Question

EXERCISE 3.3
Solve the following pair of linear equations by the substitute method

s-t=3
s/3+t/2=6​

Answer 1

Step-by-step explanation:

s = 3 + t

putting in second eq

(t + 3)/3 + t /2=6

(2(t +3) +3t)/6=6

(5t +6)/6 =6

5t +6 = 36

5t = 30

t = 6

Answer 2

From 1 we get

s = t + 3

Putting in 2 we get

(t+3)/3 + t/2 = 6

(5t+6)/6 = 6

5t+6 = 36

5t = 30

Therefore t = 6

And s = 9

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