Question

EXERCISE 3.4
26
2. sec x = 2
Find the principal and general solutions of the following equation​

Answer 1

Step-by-step explanation:

secx=2

We know, sec π/3= 2 and sec 5π/3 = sec(2π− π/3 )=sec π/3 =2

Therefore, the principal solutions are x= π/3 and 5π/3

Now, secx=sec π/3

cosx=cos π/3

x=2nπ± π/3, where n∈Z.

Therefore, the general solution is x=2nπ± π/3, n∈Z.

Answer 2

Step-by-step explanation:

sec x = 2

pricipal solution...

cos x = 1/2

cos π\3 =1/2

by allied angle formula ...

cos x = cos ( 2π -x )

cos π\3 = cos (2π - π\3 )

= cosc5π\3

hence... π\3 And 5π\3 are the principal solution ....

general solution....

cos x = 1/2

cos π\3 = 1/2

cos x = cos π\3

WKT...

cos (theta ) + cos ( alpha ) , iff (theta) = 2nπ +- (alpha) , where n € z .....

hence ..

x = 2nπ +-π\3 , n€ z .......

this is the general solution ...

I hope you understand ....

I hope you understand ....please fallow me .......