Math, asked by balasahebnage986o, 7 months ago

EXERCISE 3.6
(d) 27,63
Find the HCF of the following numbers:
(a) 18,48 (b) 30, 42
(e) 36,84 (f) 34, 102
(h) 91, 112, 49 (1) 18, 54, 81
(c) 18,60
(g) 70, 105, 175
(j) 12, 45, 75​

Answers

Answered by augastyathefinder
0

Answer:

Find the HCF of the following numbers:

(a) 18,48

Factors of 18 = 1, 2, 3, 6, 9, 18

Factors of 18 = 1, 2, 3, 6, 9, 18Factors of 48 =  1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Factors of 18 = 1, 2, 3, 6, 9, 18Factors of 48 =  1, 2, 3, 4, 6, 8, 12, 16, 24, 48Common factors = 1,2,3,6

Factors of 18 = 1, 2, 3, 6, 9, 18Factors of 48 =  1, 2, 3, 4, 6, 8, 12, 16, 24, 48Common factors = 1,2,3,6Highest common factor is 6.

Factors of 18 = 1, 2, 3, 6, 9, 18Factors of 48 =  1, 2, 3, 4, 6, 8, 12, 16, 24, 48Common factors = 1,2,3,6Highest common factor is 6.Hence, HCF = 6

(b) 30, 42

Factors of 30 = 1, 2, 3, 5, 6, 10, 15 and 30

Factors of 30 = 1, 2, 3, 5, 6, 10, 15 and 30Factors of 42 = 1, 2, 3, 6, 7, 14, 21 and 42

Factors of 30 = 1, 2, 3, 5, 6, 10, 15 and 30Factors of 42 = 1, 2, 3, 6, 7, 14, 21 and 42Common factors = 1,2,3,6

Factors of 30 = 1, 2, 3, 5, 6, 10, 15 and 30Factors of 42 = 1, 2, 3, 6, 7, 14, 21 and 42Common factors = 1,2,3,6 Highest common factor is 6.

Factors of 30 = 1, 2, 3, 5, 6, 10, 15 and 30Factors of 42 = 1, 2, 3, 6, 7, 14, 21 and 42Common factors = 1,2,3,6 Highest common factor is 6.Hence, HCF = 6

In this way you can find HCF.

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