Math, asked by anandsinghshekhawat9, 4 months ago

EXERCISE 4.3
Construct a parallelogram ABCD in which AB = 6 cm, BC = 4 cm and diagonal AC = 8.2 cm.
Construct a rhombus PORS with each side of length 4.5 cm and one diagonal of length 6 cm.​

Answers

Answered by manitaBharti
1

Answer:

First we draw a rough sketch of a quadrilateral ABCD and write down its dimensions as shown. We may divide it into two conveniently constructible Δs ABC and ACD.

Steps of construction:

1. Draw AC = 7 cm.

2. With A as centre and radius 4.5 cm, draw an arc (below AC).

3. With C as centre and radius 5.5 cm, draw another arc cutting the previous arc at

Answered by amitnrw
2

Given : a parallelogram ABCD AB=6cm , BC=4cm and diagonal AC=8.2 cm

To Find  : Construct parallelogram

Solution:

AB = CD = 6cm

BC = AD = 4 cm

Step 1 : Draw a line segment AB = 6 cm

Step 2 : Using compass width = 8.2 cm and taking A as center draw an arc

Step 3 : Using compass width = 4 cm and taking B as center draw an arc such that it intersect arc drawn in previous step at C

Step 4 : Join BC

Step 5 : Using compass width = 4 cm and taking A as center draw an arc

Step 6 : Using compass width = 6 cm and taking C as center draw an arc such that it intersect arc drawn in previous step at D

Step 7 : Join AD and CD

parallelogram ABCD is constructed

Step 1 : Draw a line segment PQ = 4.5 cm

Step 2 : Using compass width = 6 cm and taking P as center draw an arc

Step 3 : Using compass width = 4.5 cm and taking Q as center draw an arc such that it intersect arc drawn in previous step at R

Step 4 : Join QR

Step 5 : Using compass width = 4.5 cm and taking P as center draw an arc

Step 6 : Using compass width = 4.5 cm and taking R as center draw an arc such that it intersect arc drawn in previous step at S

Step 7 : Join PS and RS

 rhombus PQRS is constructed

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