Question

EXERCISE 4.3
Q.1) Solve the following linear equat
using Cramer's Rule.
ii) x+y-2z=-10,
2x+y=3z = -1, 4x+6y+z= 2​

Answer 1

x= -201/27

y= 143/27

z= -80/27

Answer 2

Answer:x = 179/11

y = -129/11

z = 80/11

Step-by-step explanation:

x+y-2z= -10, 2x+y-3z= -1, 4x+6y+z= 2

x + y  - 2z  =  - 10   Eq 1

2x + y - 3z = - 1       Eq2

4x + 6y + z = 2     Eq3

Eq 2 - Eq 1

=> x -z = 9    Eq4

Eq3  - 6*eq1

=> -2x +13z = 62    Eq5

2*Eq4  + eq 5

11z = 80

=> z = 80/11

x - z = 9

=> x = 9+80/11  =  179/11

179/11 + y -160/11 = -10

=> y = -10 - 19/11

=> y = -129/11

x = 179/11

y = -129/11

z = 80/11