Question

Exercise 5.1
Solve the following systems of simultaneous linear equations by the substitution method (1 to 4):
(ii) s-t=3
1. (i) x + y = 14
x-y=4
s + 1 = 6
(ii) 2x + 3y = 9
3x + 4y = 5
2. Yi) a + 3b = 5
7a - 8b = 6
3 2
(iv) 3x - 5y = 4
9x – 2y = 7.
(ii) 5x + 4y - 4 = 0
x - 20 = 12y.
(ii) 2x + 3y = 23
3y = 3
3. (i) 2x -
4
5x - 20 = 8y.
5x – 2 – 7 = 0
X 4. (i) mx – ny = m2 +12
Ymx+ y = a + b2
x + y = 2m
x + y = 2ab.
5. Solve 2x + y = 35, 3x + 4y = 65. Hence, find the value of
у
6. Solve the simultaneous equations 3x – y = 5, 4x – 3y = -1. Hence, find p, if y = px - 3.
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Answer 1

Answer:

5

the given equetion are...

2x+y=35.......(1)

3x+4y=65....(2)

by equetion..........1

2x+y=35

y=35-2x

putting the value of y ....in .... equetion...2

3x+4(35-2x)=65

3x+140-8x=65

140-5x=65

-5x=65-140

-5x=-75

x=-75/-5

x=15

therefore,. y=35-2×15

y=35-30

y=5