Question

EXERCISE 5.2
Find two numbers such that 3 times the larger exceeds twice the smaller by 10 and the
larger added to twice the smaller gives 6.
​

Answer 1

1. Let x>y.
2. 3x = 2y +10 ...(i)
3. x+2y =6 ...(ii)

x=6-2y

Putting ii in i, we get

• 3(6-2y) = 2y +10
• 18-6y = 2y +10
• 2y + 6y = 18 - 10
• 8y = 8
• y = 1

Thank you.

Answer 2

Answer:

please please please like and mark my answer brilliant please like my answer please