Math, asked by sham27, 1 year ago

Exercise 5.3 q no 11 ncert Class 10

Answers

Answered by SREEBHARATH
8
Given that,

Sn = 4n − n2

 

First term, a = S1 = 4(1) − (1)2 = 4 − 1 = 3

 

 

Sum of first two terms = S2

= 4(2) − (2)2 = 8 − 4 = 4

Second term, a2 = S2 − S1 = 4 − 3 = 1

d = a2 − a = 1 − 3 = −2

an = a + (n − 1)d

= 3 + (n − 1) (−2)

= 3 − 2n + 2

= 5 − 2n

a10 = 5 − 2(10) = 5 − 20 = −15

Answered by Anonymous
4
hope it helps you ......
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