EXERCISE 5A
1. The units digit of a two-digit number is 3 and seven times the sum of the digits is the
number itself. Find the number.
digit number the digit at the units place is double the digit in the tens place. The number
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Answer:
It is given that unit digit is 3 of a two digit number.
lets tens of a two digits number be x.
The number is 10x+3
sum of two digits = x+3
According to the questions,
7(x+3) = 10x+3
solving this we get
x=6
Hence the two digit number is 63.
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