EXERCISE 6.1
1. In Fig. 6. 13. lines AB and CD intersect at O. If
ZAOC +2 BOE 70 and 2 BOD - 40. find
2 BOE and reflex 2 COE.
Fig. 6.13
please answer it's very urgent
Answers
Answer:
BOE=30°
Reflex of COE=250°
Step-by-step explanation:
Given
angle AOC+BOE=70°
Angle COE = 180°-(AOC+BOE)
= 180°-70°
=110°
Reflex would be 360°-110°
= 250°
We know that Angle BOD and AOC vertically opposite angles
Angle BOD= 40°
then AOC=40°
ANGLE BOE IS
70°-AOC
70°-40°=30°
Question :-
In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.
Answer :-
Since AB is a straight line,
∴ ∠AOC + ∠COE + ∠EOB = 180°
or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]
or ∠COE = 180° – 70° = 110°
∴ Reflex ∠COE = 360° – 110° = 250°
Also, AB and CD intersect at O.
∴∠COA = ∠BOD [Vertically opposite angles]
But ∠BOD = 40° [Given]
∴ ∠COA = 40°
Also, ∠AOC + ∠BOE = 70°
∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°
Thus, ∠BOE = 30° and reflex ∠COE = 250°.
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