Question

EXERCISE 6.1
1. In Fig. 6. 13. lines AB and CD intersect at O. If
ZAOC +2 BOE 70 and 2 BOD - 40. find
2 BOE and reflex 2 COE.
Fig. 6.13

please answer it's very urgent​

Answer 1

Answer:

BOE=30°

Reflex of COE=250°

Step-by-step explanation:

Given

angle AOC+BOE=70°

Angle COE = 180°-(AOC+BOE)

= 180°-70°

=110°

Reflex would be 360°-110°

= 250°

We know that Angle BOD and AOC vertically opposite angles

Angle BOD= 40°

then AOC=40°

ANGLE BOE IS

70°-AOC

70°-40°=30°

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

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