Math, asked by naidubasker1, 3 months ago

EXERCISE - 6.2
1. Find three different solutions of the each of the following equations.
i) 3x + 4y = 7
ii) y=6x
iii) 2x - y=7
iv) 13x - 12y = 25 v) 10x + 1ly = 21
vi) x+y=0​

Answers

Answered by tmahak5
10

Answer:

1) 3x+4y=7

x= 1

=> 3×1+4y=7

=> 3+4y=7

=> 4y=7-3

=> y= 4/4

=> y= 1

if x=2

=> 3×2+4y=7

=> 6+4y=7

=> 4y=7-6

=> y=1/4

if x=3

=>3×3+4y=7

=> 9+4y=7

=> 4y=7-9

=> y=-2/4

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