Math, asked by ankitrana4196, 8 months ago

Exercise (6.3
1. What is the smallest 4-digit number such that when it is divided by 12, 18, 21 and28
it leaves remainder 3 in such case?

Answers

Answered by kaur071980gurpreet

0

Step-by-step explanation:

The greatest 4 digits number is 9999

The LCM of 12, 18, 21, 28 is 252

On dividing 9999 by 252 the remainder comes out to 171

Required number = 9999 - 171 = 9828

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