Question

EXERCISE - 6.3
Find the sum of the following APs:
0 2,7,12,..., to 10 terms.​

Answer 1

Step-by-step explanation:

Given Sequence => 2 , 7 , 12 , ...

t1 = a = 2

d = 7 - 2 = 5

Sn = n[2a + (n - 1 )d]/2

= 10 [ 2 × 2 + 9 × 5 ]/2

= 5 × ( 4 + 45 )

= 5 × 49

= 245

So S10 = 245

THANKS!!!

Answer 2

given sequence = 2, 7 , 12...

tl = 7-2 = 5

Sn =2[2a + ( n-1) d]2

10 [2 × 2 × 2 × 9 × 5 ]/2

5× ( 4 + 45)

5 × 49

= 245

so S10 = 245