Question

exercise 6.3 math question no.6

Answer 1

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Answer 2

given : QT bisect <Q
TR bisect <PRS
To prove : < QTP = 1/2 <QPR

Solve : in triangle PQR
<P + <Q = < PRS (by exterior angle property )
1/2 <P+ 1/2<Q = 1/2 <PRS
1/2 <P + <TQR = 1/2 <TRS .....(1)
IN triangle TQR
< QTR + < TQR = <TRS ......(2)
from equations (1) & (2)
1/2 <P + < TQR = < QTR + < TQR
1/2 <P = < QTR
1/2 <QPR = < QTR

........Proved


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