exercise 6.3 question 14 class 10 maths
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Next page couldn’t be attached so the explanation is here
Therefore, CE/RN= AC/PR =AD/PM
Multiplying numerator and denominator by 2
CE/RN= AC/PR=2AD/2PM
CE/RN= AC/PR = AE/PN (please refer figure)
triangle ACE congruent to triangle PRN
therefore, angle2=angle4 {cpct}
Also,
Angle1= angle3
Adding both above results
Angle BAC=angle QPR (refer figure for better understanding)
In triangleABC & trianglePQR
AB/PQ=AC/PR. ( given )
angleBAC=angleQPR
Therefore,
triangleABC is similar to triangle PQR. (By SAS test )
Next page couldn’t be attached so the explanation is here
Therefore, CE/RN= AC/PR =AD/PM
Multiplying numerator and denominator by 2
CE/RN= AC/PR=2AD/2PM
CE/RN= AC/PR = AE/PN (please refer figure)
triangle ACE congruent to triangle PRN
therefore, angle2=angle4 {cpct}
Also,
Angle1= angle3
Adding both above results
Angle BAC=angle QPR (refer figure for better understanding)
In triangleABC & trianglePQR
AB/PQ=AC/PR. ( given )
angleBAC=angleQPR
Therefore,
triangleABC is similar to triangle PQR. (By SAS test )
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