Math, asked by ayushikumarikumari75, 3 months ago


EXERCISE 7.5
Factorize the following algebraic expressions by splitting the middle term:
(a) r? - 21x + 108 (b) 40 + 3p-p?
(c) 9x -?-20
(e) (x2 - 5x)2 - 36 (f) x-x-56 (g) 2 - 11x + 24
(1) 8x? - 22xy + 15y? () 3a + 1lab +662 (k) 2a - 17a - 30
(m) 2x² + 7x - 4 (n) 5a? + 13a + 6 (0) 3(2x - y)² + 14(2x - y) + 8
(d) (x + 7)(x-10)+16
(1) 2(3x-4y)-3(37–4




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when a question exercise 7.5

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tani712

tani712

03.02.2018

Math

Secondary School

answered

X2-21x+108 factorise it

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Raghav1111111111

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Factoring x2-21x+108

The first term is, x2 its coefficient is 1 .

The middle term is, -21x its coefficient is -21 .

The last term, "the constant", is +108

Step-1 : Multiply the coefficient of the first term by the constant 1 • 108 = 108

Step-2 : Find two factors of 108 whose sum equals the

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