Question

EXERCISE 7 (b)
A sequence :{ an} is given by the sequence an = 10-3n, ne N€N. Prove that it is an A.P.​

Answer 1

Answer:

Mark me as brainlist

Step-by-step explanation:

$\frac{ \frac{ \sqrt[ \sqrt[ | | | < < < < < < < < < < \frac{ \geqslant \geqslant \leqslant \frac{ \frac{x { {?}^{?} }^{2} }{?} }{?} }{?} | | | ]{?} ]{?} }{?} }{?}$

Answer 2

An = 10 - 3n

Putting value of n,

Let n = 1 ,

Then,

A1 = 10 - 3 *1

A1 = 7

For n = 2,

A2 = 10 - 3 *2

A2 = 10 - 6 = 4

For n = 3 ,

A3 = 10 - 3 * 3

A3 = 10 - 9 = 1

Now,

A2 - A1 = 4 - 7 = - 3 = d

A3 - A2 = 1 - 4 = - 3 = d

Since, Difference is common.

So, Common difference is same.

Hence, The given sequence is in A. P.