Math, asked by jeenapariyar123, 9 months ago

EXERCISE 7B
1. Twice a number when decreased by 7 gives 45. Find the number.​

Answers

Answered by ugfctdx
0

Answer:

Step-by-step explanation: GOD NO

Answered by vaidehi7954
2

Step-by-step explanation:

Let the no be x

so, twice a no= 2x, when decrease by 7= 2x-7 ,gives 45

Therefore= 2x-7=45

=2x= 45=7  9 by transposition)

=2x= 38

=x=38/2

=x= 19

The no is 19

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