Question

Exercise 8.3
1. Solve the following linear equations and verify the solution
e.4 (7-3z)+1=5-3 (5z+2)​

Answer 1

Answer:

L.H.S

4(7-3z)+1

=> 28-12z+1

=> 29-12z

(let put z=10)

=> 29-12×10

=>29-120= -91...

R.H.S

5-3(5z+2)

=>5-15z-6

=> -15z-1

=> z=10

=>-15×10-1

=> -150-1= -151...

SO, L.H.S IS NOT EQUAL TO R.H.S...

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