Math, asked by tishagupta10, 6 months ago


Exercise 9.1
1. Use x' as the variable and translate each of the following statements into an equation:
(i) The sum of two consecutive numbers is 21.
(ii) Twice a number subtracted from 10 gives 2.
(iii) One-eighth of a number added to 6 gives 8.
(iv) Twice a number when divided by 5 gives 6.
(v) A number when divided by 7 gives a quotient 6 and a remainder 2.

Pls answer tomorrow is my test​

Answers

Answered by priyanshisengar2006
2

Answer:

1/) x+(x+1) =21

2) 10-2x=2

3) (1/8x)+6=8

4) 2x/5=6

Answered by nsvs2511
2

Answer:

i)Let the two consecutive numbers be x,x+1

Step-by-step explanation:

Their sum =21

This implies x+x+1=21

2x+1=21

2x=21-1=20

x=20÷2=10

x=10

x+1=11

ii)Let the number be x

Twice the number=2x

2x subtracted from 10 gives 10-2x

Result=2

This implies 10-2x=2

2x=2-10=-8

-x=-8/4=-4

-x=-4

x=4

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