Math, asked by shubhanshunagar2008, 5 hours ago

EXERCISE 9.3 1. Carry out the multiplication of the expressions in each of the following pairs. (1) 4p, 9+r (ii) ab, a-b (111) a + b, 7a²b2 (V) P9 + gr + rp, 0 (TV) a² - 9,4a 2. Com​

Answers

Answered by prathamjangid3242
1

Answer:

ufzrusursjtsitsututxitx

Step-by-step explanation:

x7txitxogxotdt8dits7rs7s7rzursursurursurditditsit7dit

Answered by khesantosh
0

Answer:

Ncert solutions

Our top 5% students will be awarded a special scholarship to Lido.

Set your child up for success with Lido, book a class today!

Mathematics

Science

Chapters in NCERT Solutions - Mathematics , Class 8

Exercises in Algebraic Expressions and Identities

Question 1

Q1) Carry out the multiplication of the expressions in each of the following pairs:

(i) 4p,\ q+r4p, q+r

(ii) ab,\ a\ -\ bab, a − b

(iii) a+b,\ 7a^2b^2a+b, 7a

2

b

2

(iv) a^2-9,\ 4aa

2

−9, 4a

(v) pq+qr+rp, 0

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Solution:

(i) 4p\times\left(q+r\right)=4p\times q+4p\times r\ =\ 4pq+4pr4p×(q+r)=4p×q+4p×r = 4pq+4pr

(ii) ab\times\left(a-b\right)=ab\times a-ab\times b=a^2b-ab^2ab×(a−b)=ab×a−ab×b=a

2

b−ab

2

(iii) \left(a+b\right)\times7a^2b^2=a\times7a^2b^2+b\times7a^2b^2=7a^3b^2+7a^2b^3(a+b)×7a

2

b

2

=a×7a

2

b

2

+b×7a

2

b

2

=7a

3

b

2

+7a

2

b

3

(iv) \left(a^2-9\right)\times4a=a^2\times4a-4a\times9=4a^3-36a(a

2

−9)×4a=a

2

×4a−4a×9=4a

3

−36a

(v) (pq+qr+rp) x 0 = pq x 0 + qr x 0 + rp x 0

= 0 + 0 + 0 = 0

Similar questions