Question

Exercise 9. In Geometry Figure 35 below, AB = BC = CD. If the area of triangle
CDE is 42, what is the area of triangle ADG ?​

Answer 1

Answer:

Here is the easiest way - :

Step-by-step explanation:

Since the theoram says - in two similar triangles, the ratio of there areas is the square of the ratio of there sides.

Area of CDE /area of ADG=(CD/AD)^2

Here in figure suppose CD=x, then AD =3x

(Already mentioned in question AB=BC=CD)

So (area of CDE)/(area of ADG) =(x/3x)^2

Setting x to a value of 1, 42(/area of ADG) =1/9

Area of ADG =378

378