Question

EXERCISE
A block of mass 10 kg is moving on a rough sur
al force acting on the
loving on a rough surface as shown in figure. The frictional force actir
v = 4 m/s
) 20 N
F = 20 N
10 kgH
TTTTTTTTTTTTTTTTTTTTTT
u = 0.6
(2) 60 N
(4) 80 N
40 N
​

Answer 1

frictional force=60N

Explanation:

as we know ,

frictional firce=u N

N=mg

Fr=umg

GIVEN:

u=0.6, m=10kg, g=10

so,

Fr=0.6×10×10

Fr=60N Answer