Question

EXERCISE b
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1 The sum of two numbers is 50 and their difference is 16. Find the numbers.​

Answer 1

Step-by-step explanation:

$let \: the \: two \: number \: be \: x \: and \: y \\ sum \: of \: two \: number \: = 50 \\ x + y = 50.....(1) \\ difference \: of \: two \: number \: = 16 \\ x - y = 16.......(2) \\ then \: according \: to \: question \: \\ using \: substitution \: method \: \\ in \: eq.(2) \\ x - y = 16 \\ x = 16 + y......(3)eq. \\ now \: put \: the \: value \: of \: x \: on \: (1)eq. \\ x + y = 50 \\ 16 + y + y = 50 \\ 16 + 2y = 50 \\ 2y = 50 - 16 \\ 2y = 34 \\ y = \frac{34}{2 } \\ y = 17 \\ putting \: the \: value \: of \: y \: on \: (3)eq. \\ x = 16 + y \\ x = 16 + 17 \\ x = 33 \\ therefore \: the \: two \: number \: be \: 33 \: and \: 17 \\ pls \: mark \: it \: as \: a \: brainliest.$

Answer 2

$\large\underline{ \underline{ \sf \: Solution : \: \: \: }}$

Let , the two numbers be x and y

By the given condition ,

$\star$x + y = 50 -----------(i)

$\star$x - y = 16 ---------- (ii)

Using elimination method , Add equation (i) and equation (ii)

$\sf \implies (x + y) + (x - y) = 50 + 16 \\ \\ \sf \implies</p><p>2x = 66\\ \\ \sf \implies </p><p>x = 33$

Put the value of x = 33 in equation (i)

$\sf \implies 33 + y = 50 \\ \\ \sf \implies</p><p>y = 50 - 33 \\ \\ \sf \implies </p><p>y = 17</p><p>$

$\therefore$The required numbers are 33 & 17