Math, asked by shawneha126, 4 months ago

Exercise
if A-5,A+3 and 7a+1 are 3 consecutive terms of a geometric progression then find the value of a

Answers

Answered by nallasreeja123

1

Answer:

(a+3)-(a-5)=(7a+1)-(a+3)

a+3-a+5=7a+1-a-3

8=6a-2

6a=10

a=10/6

a=5/3

Step-by-step explanation:

hope it helped you

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