Exercises 1. A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen g Calculate the percentage composition of the compound by weight.
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%age of oxygen = wt. of oxygen/wt. of ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀sample×100.
⠀⠀⠀⠀⠀⠀⠀⠀⠀= 0.14/0.24×100 = 60%
%age of boron =wt. of boron/wt. of ⠀⠀⠀⠀⠀⠀⠀⠀⠀sample ×100
⠀⠀⠀⠀⠀⠀⠀⠀⠀= 0.96/0.24×100 = 40%
hope it helps you
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Answer:
Explanation:
Total mass of compound = 0.24 g
Mass of boron in it = 0.096 g
Therefore % composition by weight of boron = (Mass of boron/ Total mass of compound)*100
= (0.096/0.24)*100
= 40 %
Mass of oxygen in the compound = 0.144 g
Therefore % composition by weight of oxygen = (Mass of oxygen/ Total mass of compound)*100
= (0.144/0.24)*100
= 60 %.
The compound is made up of only boron and oxygen, therefore the % composition of the componenets sum to 100% (60% + 40%)
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