Question

Exit lands on an aircraft carrier at 60 metre per second it stop in 2.0 s what is the displacement of the plane when it stop

Answer 1

Answer:

The displacement made by the plane when it stops is 60 m.

Explanation:

The initial velocity of the plane, u = 60 m/s

The plane finally stops. So the final velocity, v = 0 m/s

Time taken to stop the plane, t = 2 s

The acceleration of the plane can be obtained from the 1st equation of motion.

v = u + at

a = (v - u) / t

a = (0 - 60) / 2

a = -30 m/s²

The value of acceleration is negative because the plane is under a retarding motion.

Distance covered by the plane is calculated from the 3rd equation of motion.

v² - u² = 2aS

S = (v² - u²) / 2a

S = (0² - 60²) / (2 × -30)

S = -3600 / -60

S = 60 m