Question

Exothermic process is :
O Na ® Na+ + e
O O + e-0-
0— + e-
Ⓡ 0-2
OC @ Cl + e-
hi​

Answer 1

First electron affinity of Cl (Negative exothermic energy because energy released)

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e −

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl −

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O −

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O − +e

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O − +e ⊝

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O − +e ⊝ →O

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O − +e ⊝ →O 2−

First electron affinity of Cl (Negative exothermic energy because energy released)Cl+e − →Cl − → exothermic ⋅ Second electron affinity of O (supply energy to overcome force of electronic repulsion)O − +e ⊝ →O 2− → endothermic