Question

expСпп
In Young's double-slit experiment using monochromatic light of
wavelength lambda, the intensity of light at a point on the screen where
path difference is lambda, is K units. What is the intensity of light at a
point where path difference is 1/3?​

Answer 1

Answer:

It is given that,

intensity, Io=K

we know that,

I=Io cos²∅/2

where,∆∅=2π/lambda×∆x

∆x=path difference

∆∅=2π/lambda×lambda/3

∆∅=2π/3

substitute the phase difference in the above equation,

I=Io cos²2π/3×2

I=Io cos²π/3

I=K×1/4

I=K/4

Explanation:

Hope it helps you.....