Question

expand (1-1/a) cube ​

Answer 1

Step-by-step explanation:

(1-1/a)³=1³-(1/a)³-3(1)²(1/a)+3(1)(1/a)²

=1-1/a³-3/a+3/a²

Answer 2

Answer:

$1 - \frac{1}{a^3} - \frac{3}{a} + \frac{3}{a^2}$ is the expansion of $(1 - \frac{1}{a})^3$.

Step-by-step explanation:

Explanation:

Formula of $(a - b)^3$ = $a^3 - b^3 -3a^2b + 3ab^2$.

Therefore, from the question we have,$(1 - \frac{1}{a})^3$.

Now from the formula,

$(1 - \frac{1}{a})^3$ = $1^3 - (\frac{1}{a})^3 - 3. 1^2.(\frac{1}{a}) + 3(1).(\frac{1}{a} )^2$

⇒$(1 - \frac{1}{a})^3$ = $1 - \frac{1}{a^3} - \frac{3}{a} + \frac{3}{a^2}$

Final answer:

Hence, the expansion of $(1 - \frac{1}{a})^3$ is $1 - \frac{1}{a^3} - \frac{3}{a} + \frac{3}{a^2}$.

#SPJ3