Question

expand ( 1/2x - y ) cube ​

Answer 1

Answer:

The expanded form is:

=$(\frac{1}{2x-y})^3$

=$\frac{1^3}{(2x-y)^3}$

=$\frac{1}{(2x)^3-3.(2x)^2.y+3.2x.y^2-y^3}$

=$\frac{1}{8x^3-12x^2y+6xy^2-y^3}$   ,which is the answer.