Question

expand 1 /3 x minus 2 /3 y wholepower cube​

Answer 1

Answer:

$( \frac{1}{3} x - \frac{2}{3} y) {}^{3} \\ ( \frac{1}{3} x) {}^{3} - ( \frac{2}{3} y) {}^{3} - 3( \frac{1}{3} x) {}^{2} ( \frac{2}{3} y) + 3( \frac{1}{3} x)( \frac{2}{3} y) {}^{2} \\ \frac{1}{27} x {}^{3} - \frac{8}{27} y {}^{3} - 3( \frac{1}{9} x {}^{2} )( \frac{2}{3} y) + 3( \frac{1}{3} x)( \frac{4}{9} y {}^{2} ) \\ \frac{1}{27} x {}^{3} - \frac{8}{27} y {}^{3} - \frac{2}{9} x {}^{2} y + \frac{4}{9} xy {}^{2}$

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Answer 2

Step-by-step explanation:

(1/3x - 2/3 y )^3

= (1/3)^3 [x -2y]^3

= 1/27( x^3 - (2y)^3 - 3 × X × 2Y(x - 2y)

=1/27( x^3 - 8y^3 -6xy(x - 2y)

1/27 ( x^3 - 8y^3 - 6x^2y + 12xy^2)