Math, asked by wilmavs4u, 9 months ago

Expand : 1. (3a + 1/3a) ^ 2
2. (2x + y + z) ^ 2

Answers

Answered by maitreyee221
3

Answer:

1.

By using Identity a2-2ab+b2

(3a)2-2*3a *1/3b+(1/3b)2

9a2-2ab+1/9b2

2.

(2x)2+(y)2+(z)2+2(2xy)+2yz+2(2xz)

(Identity:x2+y2+z2+2xy+2yz+2zx)

4x2+y2+z2+4xy+2yz+4zx

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Answered by Anonymous
1

{(3a +  \frac{1}{3a})}^{2}

 ({3a})^{2}  +  ({ \frac{1}{3a} })^{2}  + 2 \times 3a \times  \frac{1}{3a}

Answer

 {9a}^{2}  +  \frac{1}{ {9a}^{2} }  + 2

2 nd Question

(2x + y + z) ^ 2 </p><p>

 {(2x)}^{2}  +  {(y)}^{2}  +  {(z)}^{2}  + 2 \times 2x \times y + 2 \times y \times z + 2 \times z \times 2x

Answer

 {4x}^{2}  +  {y}^{2}  +  {z}^{2}  + 4xy + 2 yz + 4xz

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