Question

expand (1/×+4/3)^3 please solve it I will mark you as a brainliest ​

Answer 1

Answer:

Hi there, here we have,

$(\frac{1}{x}+\frac{4}{3})^3$

Formula = $(a+b)^3 = a^3+b^3+3a^2b+3ab^2$

a = $\frac{1}{x}$

b = $\frac{4}{3}$

= $(\frac{1}{x}+\frac{4}{3})^3 = (\frac{1}{x})^3+(\frac{4}{3})^3+3*(\frac{1}{x})^2*\frac{4}{3}+3*\frac{1}{x}*(\frac{4}{3})^2$

=> $\frac{1}{x^3}+\frac{64}{27}+3*\frac{1}{x^2}*\frac{4}{3}+3*\frac{1}{x}*\frac{16}{9}$

=> $\frac{1}{x^3}+\frac{64}{27}+\frac{1}{x^2}*4+\frac{1}{x}*\frac{16}{3}$

=> $\frac{1}{x^3}+\frac{64}{27}+\frac{4}{x^2}+\frac{16}{3x}$

So this is the expanded solution,

Hope this helps you.

All the best.