Math, asked by bornalig296, 5 months ago

Expand (1/a+2b+c)^2​

Answers

Answered by Swetha03K
1

Answer:

1/a² + 4b² + c² + 4b/a + 4bc + 2c/a

Step-by-step explanation:

Using the formula:

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Here,

a = 1/a     ;     b = 2b    ;    c = c

Substituting the values in the formula,

(1/a+2b+c)² = (1/a)² + (2b)² + (c)² + 2(1/a)(2b) + 2(2b)(c) + 2(c)(1/a)

                   = 1/a² + 4b² + c² + 4b/a + 4bc + 2c/a

Answered by Princessade
0

Answer:

​ 4 b c a 2 + 4 b 2 a 2 + 4 b a + 2 c a + c 2 a 2 + 1 /a 2

here is the answer I hope it helps

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