EXPAND===↓↓↓↓
1. (k + 4)³
2. (7x + 8y)³
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1
(a + b) {}^{3} = a {}^{3} + b {}^{3} + 3a {}^{2} b + 3ab {}^{2}(a+b)3=a3+b3+3a2b+3ab2
===>
\red{ \boxed{a = k \: and \: b = 4}}a=kandb=4
===> Put in identity
===>
k {}^{3} + (4) {}^{3} + 3(k) {}^{2} 4 + 3(k)(4) {}^{2}k3+(4)3+3(k)24+3(k)(4)2
===>
\green{ \boxed{ \underline{(k + 4) {}^{3} = k {}^{3} + 64 + 12k {}^{2} + 48k}}}(k+4)3=k3+64+12k2+48k
2.
(a + b) {}^{3} = a {}^{3} + b {}^{3} + 3a {}^{2} b + 3ab {}^{2}(a+b)3=a3+b3+3a2b+3ab2
===>
\red{ \boxed{a = k \: and \: b = 4}}a=kandb=4
===> Put in identity
===>
k {}^{3} + (4) {}^{3} + 3(k) {}^{2} 4 + 3(k)(4) {}^{2}k3+(4)3+3(k)24+3(k)(4)2
===>
\green{ \boxed{ \underline{(k + 4) {}^{3} = k {}^{3} + 64 + 12k {}^{2} + 48k}}}(k+4)3=k3+64+12k2+48k
2.
btw which clas
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MEDICAL COLLEGE
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Answered by
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1.k³+64+12k(k+4) = (k+4)³
2.343x³+512y³+168xy(7x+8y) =(7x+8y)³
2.343x³+512y³+168xy(7x+8y) =(7x+8y)³
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