Expand (1/x+y/3)^3 using the correct identity.
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(1/x+y/3)³
(a+b)³=a³+b³+3ab(a+b)
= (1/x)³+(y/3)³+3(1/x)(y/3)(1/x+y/3)
= 1/x³+y³/27+y/x(1/x+y/3)
= 1/x³+y³/27+y/x²+y²/3x
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(a+b)³=a³+b³+3ab(a+b)
= (1/x)³+(y/3)³+3(1/x)(y/3)(1/x+y/3)
= 1/x³+y³/27+y/x(1/x+y/3)
= 1/x³+y³/27+y/x²+y²/3x
Hope it helps ☺
Please mark as Brainliest ☺
Answered by
8
= 1/x³+y³/27+y/x²+y²/3x
Hope it helps ☺
Please mark as Brainliest ☺
Hope it helps ☺
Please mark as Brainliest ☺
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