expand (1+y+y²)⁴. by binomial theorem
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let y+y²=t
then (1+t)⁴= 1 + 4t + 6t² + 4t³+ t⁴
t=y(1+y)
t²=y²(1+2y+y²)
t³=y³(1+3y+3y²+y³)
t⁴=y⁴(1+4y+6y²+4y³+y⁴)
put the values to get the answer.
you could use multinomial theorm for simplicity.
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