Question

expand (1a/4-1b/2+1)square

Answer 1

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Heya

Question :-

(1a/4 - 1b/2 + 1)^2 = ?

Answer :-

Using identity

⏩(x - y + z)^2 = x^2 + y^2 + z^2 - 2xy - 2yz + 2zx⏪

Here x = 1a/4 , y = 1b/2 and z = 1

= (1a/4)^2 + (1b/2)^2 + (1)^2 - 2(1a/4)(1b/2) - 2(1b/2)(1) + 2(1)(1a/4)

$= \frac{ {a}^{2} }{16} + \frac{ {b}^{2} }{4} + 1 - \frac{ab}{4} - b + \frac{a}{2}$

Hope this helps you.