Expand - 1sum (2x + 3y - 4z)² 2sum (x + 3y)³
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Answer:
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(2x+3y+4z)
2
=(2x)
2
+(3y)
2
+(4z)
2
+(2×2x×3y)+(2×3y×4z)+(2×4z×2x)
(∵(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca)
=4x
2
+9y
2
+16z
2
+12xy+24yz+16zx
Hence, (2x+3y+4z)
2
=4x
2
+9y
2
+16z
2
+12xy+24yz+16zx.
4x
2
+9y
2
+16z
2
+12xy+24yz+16zx
Step-by-step explanation:
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