Expand (2+1/X)^3 using identities
Answers
Answered by
0
Answer:
\begin{gathered} = ( {2x + 1})^{3} \\ = {2x}^{3} + {1}^{3} + 3 (2x)^{2} (1) + 3 (2x) {1}^{2} \\ = {8x}^{3} + 1 + 12 \: {x}^{2} + 6x \end{gathered}
=(2x+1)
3
=2x
3
+1
3
+3(2x)
2
(1)+3(2x)1
2
=8x
3
+1+12x
2
+6x
Heya friend! :)
The identity used in it is
= ({a + b})^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2} b + 3a {b}^{2}=(a+b)
3
=a
3
+b
3
+3a
2
b+3ab
2
HOPE THIS HELPS YOU :)
Step-by-step explanation:
- hope it helps you!
Answered by
4
Answer:
The (x+1)3 formula can be verified or proved by multiplying (x + 1) three times, i.e,
(x+1)3 = (x+1)(x+1)(x+1)
(x+1)3 = [x2 + x + x + 1] (x + 1)
= (x + 1) [x2 + 2x + 1]
= x3 + 2x2 + x + x2 + 2x + 1
= x3 + 3x2 + 3x + 1
Therefore, (x+1)3 = x3 + 3x2 + 3x + 1
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