Expand 2/3x - 3/4y square
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16
Given :-
➪ (⅔ x - ¾ y)²
To expand it :-
Identity used :-
➪ (a-b)² = a² + b² - 2ab
➪ a = ⅔ x and b = ¾ y
➪ (⅔ x)² + (¾ y)² - 2 × ⅔ x × ¾ y
➪ ⁴⁄₉ x² + ⁹⁄₁₆ y² - xy
Learn more :-
➪ (a+b)² = a² + b² + 2ab
➪ (a+b)² - (a-b)² = 4ab
➪ (a+b) (a-b) = a² - b²
➪ (a+b)² + (a-b)² = 2(a² + b²)
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2
( \frac{2}{3} x - \frac{3}{4}y ) {}^{2} \\ \\ = > \frac{2}{3} x {}^{2} + \frac{3}{4} y {}^{2} - 2 \times ( \frac{2}{3} x) \times ( \frac{3}{4} y) \\ \\ = > \frac{4}{9} x {}^{2} + \frac{9}{16} y {}^{2} - xy
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