Expand (-2×+3y+2y)^2
factorise 6×^2+7×-3
factorise2×^2-7×-15
factorise2×^3-3×^2-17×+30
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i)(-2x+5y)^2
=4x^2+25y^2-20xy
ii)6x^2+9x-2x-3
=2x(3x-1)+3(3x-1)
=(2x+3)(3x-1)
=x=-3/2,1/3
iii)2x^2-10x+3x-15=0
=2x(x-5)+3(x-5)
=(x-5)(2x+3)
=x=5,-3/2
iv)
(X-2)(x+3)(2x-5)
Answer
let p(x) =23 – 32 – 17 + 30
p(1) = 2 – 3 – 17 + 30 = 12 ≠ 0
p(2) = 2(2)3 – 3(2)2 – 17(2) + 30 = 46 – 46 =0
hence x – 2 is a factor of p(x) 2x2 + x – 15
p(x) = (x – 2) (2x2 + x – 15)
= (x – 2) (2x2 + 6x – 5x – 15)
= (x – 2) (2x (x + 3) – 5(x – 3))
= (x – 2) (2x – 5) (x + 3)
Hope that helps
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