Question

expand : ( 2a+3b+4c)^2

Answer 1

Here the sum is (2a+3b+4c)^2
for this the formula is (a+b+c)^2 = (2a)^2+(3b)^2+(4c)^2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

   solution =                     4a^2+9b^2+16c^2+12ab+24bc+16ac
           

pls mark as brainlist answer pls.                                         

Answer 2

Hi

here is ur answer:-

( 2a + 3b + 4c )²

dear , we need a formula which is

( a + b + c )² = a² + b² + c² + 2 ( ab + bc + cb )

now ,

( 2a )² + ( 3b )² + ( 4c )² + 2 { ( 2a.3b + 3b.4c + 4c.2a ) }

= 4a² + 9b² + 16c² + 2 { ( 6ab + 12bc + 8ca )}

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