Question

expand(2a-3b-c) square​

Answer 1

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Answer 2

Given,

An algebraic expression  (2a-3b-c$)^{2}$.

To Find,

The value of this algebraic equation.

Solution,

We can solve this using two following ways.

• One is using the formula which is (a+b+c$)^{2}$=$a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$.
• Another is with the general method of assuming the first two sums to be one , like for(a+b+c$)^{2}$=((a+b)+c$)^{2}$=$(a+b)^{2}+c^{2}+2(a+b)c$.

Here we will solve using the formula.

So   (2a-3b-c$)^{2}$

=$(2a)^{2}+(-3b)^{2}+(-c)^{2}+2(2a)(-3b)+2(-3b)(-c)+2(-c)(2a)$

=4$a^{2}$+9$b^{2}$+$c^{2}$-12ab+6bc-4ac.

Hence, The simplified value of   (2a-3b-c$)^{2}$ is 4$a^{2}$+9$b^{2}$+$c^{2}$-12ab+6bc-4ac.