Question

Expand (2a-4b+3c)^2 using identity

Answer 1

Answer:

4a²+16b²+9c²-16ab-24bc+12ca

Step-by-step explanation:

We have used the identity,

(a+b+c)² = a²+b²+c²+2ab+2bc +2ca.

(2a-4b+3c)²

= (2a)²+(-4b)²+(3c)²+(2×2a×-4b)+(2×-4b×3c)+(2×3c×2a)

= 4a²+16b²+9c²-16ab-24bc+12ca