Question

expand (2a+b-c)square​

Answer 1

Step-by-step explanation:

(2a+b-c)²

= [(2a)+b+(-c)]²

= (2a)²+(b)²+(-c)²+2×2a×b+2×b×(-c)+2×(-c)×2a

= 4a²+b²+c²+4ab-2bc-4ca

Answer 2

Step-by-step explanation:

(2a+b-c)^2 =(2a)^2+b^2+(-c)^2+2(2a)(b)+2b(-c)+2(-c)(2a)

4a^2+b^2+c^2+4ab-2bc-4ac