Question

expand (√2m+√2n) ^2​

Answer 1

Step-by-step explanation:

${( \sqrt{2} m + \sqrt{2}n) }^{2} \\ = {( \sqrt{2}m) }^{2} + (2 \times ( \sqrt{2} m \times \sqrt{2} n)) + {( \sqrt{2} n)}^{2} \\ = 2 {m}^{2} + (2 \times 2mn) + 2 {n}^{2} \\ = 2 {m}^{2} + 4mn + 2 {n}^{2}$

Answer 2

Answer:

x+  

x

1

​  

=6

⇒(x+  

x

1

​  

)  

2

=x  

2

+  

x  

2

 

1

​  

+2x.  

x

1

​  

 

                          =x  

2

+  

x  

2

 

1

​  

+2

⇒x  

2

+  

x  

2

 

1

​  

=(x+  

x

1

​  

)  

2

−2=6  

2

−2=34

⇒(x  

2

+  

x  

2

 

1

​  

)  

2

=x  

4

+  

x  

4

 

1

​  

+2x  

2

.  

x  

2

 

1

​  

 

                             =x  

4

+x  

4

+  

x  

4

 

1

​  

+2

⇒x  

2

+  

x  

2

 

1

​  

=(x  

2

+  

x  

2

 

1

​  

)  

2

−2=34  

2

−2