Question

. Expand : (2x + 1)ᶟ​

Answer 1

Answer:

$\huge{\underline{\underline{Given→}}}$

• $\sf\green{Equation=(2x+1)^3}$

$\huge{\underline{\underline{To\:Find→}}}$

$\sf\purple{→Expanded\:form\:of\:the\:given\:equation.}$

$\huge{\underline{\underline{Answer→}}}$

$\sf\blue{→(2x+1)^3}$

$\sf\blue{→(2x)^3+(1)^3+3(2x)(1)(2x+1)}$

$\sf\blue{→(2x)^3+1+6x(2x+1)}$

$\sf\blue{→(2x)^3+1+(6x)(2x)+(6x)(1)}$

$\sf\blue{→8x^3+1+12x^2+6x}$

$\sf\blue{→8x^3+12x^2+6x+1}$

$\sf{\boxed{\boxed{\pink{→8x^3+12x^2+6x+1✔}}}}$

$\bold{\underline{\underline{Identity\:used→}}}$

$\sf\color{blue}{→(a+b)^3=a^3+b^3+3ab(a+b)}$

HOPE IT HELPS.

Answer 2

Answer:

$→(2x+1) </p><p>3</p><p> </p><p></p><p>\sf\blue{→(2x)^3+(1)^3+3(2x)(1)(2x+1)}→(2x) </p><p>3</p><p> +(1) </p><p>3</p><p> +3(2x)(1)(2x+1)</p><p></p><p>\sf\blue{→(2x)^3+1+6x(2x+1)}→(2x) </p><p>3</p><p> +1+6x(2x+1)</p><p></p><p>\sf\blue{→(2x)^3+1+(6x)(2x)+(6x)(1)}→(2x) </p><p>3</p><p> +1+(6x)(2x)+(6x)(1)</p><p></p><p>\sf\blue{→8x^3+1+12x^2+6x}→8x </p><p>3</p><p> +1+12x </p><p>2</p><p> +6x</p><p></p><p>\sf\blue{→8x^3+12x^2+6x+1}→8x </p><p>3</p><p> +12x </p><p>2</p><p> +6x+1</p><p></p><p>\sf{\boxed{\boxed{\pink{→8x^3+12x^2+6x+1✔}}}} </p><p>→8x </p><p>3</p><p> +12x </p><p>2</p><p> +6x+1✔</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\bold{\underline{\underline{Identity\:used→}}} </p><p>Identityused→</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\sf\color{blue}{→(a+b)^3=a^3+b^3+3ab(a+b)}→(a+b) </p><p>3</p><p> =a </p><p>3</p><p> +b </p><p>3</p><p> +3ab(a+b)$