Question

expand (2x-1/3y)^3
please give the steps​

Answer 1

Answer:

this is wht i got

2x^3 - (2x^2)/(3y) + (2x)/(3y^2) - 1/(9y^3)

Step-by-step explanation:

(a-b)= a^3 - 3(a^2)b + 3a(b^2) - b^3

so,

2x^3 - 3.(2x^2)/(3y)  + 3.(2x)/(3y^2) - 1/(9y^3)

2x^3 - (2x^2)/(3y) + (2x)/(3y^2) - 1/(9y^3)

:)